to iterate through an SBValue instance by treating it as the head of a linked
list. API program must provide two args to the linked_list_iter() method:
the first being the child member name which points to the next item on the list
and the second being a Python function which an SBValue (for the next item) and
returns True if end of list is reached, otherwise it returns False.
For example, suppose we have the following sample program.
#include <stdio.h>
class Task {
public:
int id;
Task *next;
Task(int i, Task *n):
id(i),
next(n)
{}
};
int main (int argc, char const *argv[])
{
Task *task_head = new Task(-1, NULL);
Task *task1 = new Task(1, NULL);
Task *task2 = new Task(2, NULL);
Task *task3 = new Task(3, NULL); // Orphaned.
Task *task4 = new Task(4, NULL);
Task *task5 = new Task(5, NULL);
task_head->next = task1;
task1->next = task2;
task2->next = task4;
task4->next = task5;
int total = 0; // Break at this line
Task *t = task_head;
while (t != NULL) {
if (t->id >= 0)
++total;
t = t->next;
}
printf("We have a total number of %d tasks\n", total);
return 0;
}
The test program produces the following output while exercising the linked_list_iter() SBVAlue API:
task_head:
TypeName -> Task *
ByteSize -> 8
NumChildren -> 2
Value -> 0x0000000106400380
ValueType -> local_variable
Summary -> None
IsPointerType -> True
Location -> 0x00007fff65f06e60
(Task *) next = 0x0000000106400390
(int) id = 1
(Task *) next = 0x00000001064003a0
(Task *) next = 0x00000001064003a0
(int) id = 2
(Task *) next = 0x00000001064003c0
(Task *) next = 0x00000001064003c0
(int) id = 4
(Task *) next = 0x00000001064003d0
(Task *) next = 0x00000001064003d0
(int) id = 5
(Task *) next = 0x0000000000000000
llvm-svn: 135938
4822505338