Pass a && to getLazyBitcodeModule.

This forces callers to use std::move when calling it. It is somewhat odd to have
code with std::move that doesn't always move, but it is also odd to have code
without std::move that sometimes moves.

llvm-svn: 217049
This commit is contained in:
Rafael Espindola
2014-09-03 17:31:46 +00:00
parent 99b96f42d6
commit 688121571a
7 changed files with 15 additions and 12 deletions

View File

@@ -53,7 +53,8 @@ static std::unique_ptr<Module> getLazyModuleFromAssembly(LLVMContext &Context,
writeModuleToBuffer(parseAssembly(Assembly), Mem);
std::unique_ptr<MemoryBuffer> Buffer =
MemoryBuffer::getMemBuffer(Mem.str(), "test", false);
ErrorOr<Module *> ModuleOrErr = getLazyBitcodeModule(Buffer, Context);
ErrorOr<Module *> ModuleOrErr =
getLazyBitcodeModule(std::move(Buffer), Context);
return std::unique_ptr<Module>(ModuleOrErr.get());
}