[SLP] Outline code for the check that instruction users are part of

vectorization tree, NFC.

llvm-svn: 309284
This commit is contained in:
Alexey Bataev
2017-07-27 15:48:44 +00:00
parent 64a795c5f5
commit 07b96e8e96

View File

@@ -416,6 +416,9 @@ public:
private:
struct TreeEntry;
/// Checks if all users of \p I are the part of the vectorization tree.
bool areAllUsersVectorized(Instruction *I) const;
/// \returns the cost of the vectorizable entry.
int getEntryCost(TreeEntry *E);
@@ -1702,6 +1705,13 @@ bool BoUpSLP::canReuseExtract(ArrayRef<Value *> VL, Value *OpValue) const {
return true;
}
bool BoUpSLP::areAllUsersVectorized(Instruction *I) const {
return I->hasOneUse() ||
std::all_of(I->user_begin(), I->user_end(), [this](User *U) {
return ScalarToTreeEntry.count(U) > 0;
});
}
int BoUpSLP::getEntryCost(TreeEntry *E) {
ArrayRef<Value*> VL = E->Scalars;
@@ -1742,10 +1752,7 @@ int BoUpSLP::getEntryCost(TreeEntry *E) {
// If all users are going to be vectorized, instruction can be
// considered as dead.
// The same, if have only one user, it will be vectorized for sure.
if (E->hasOneUse() ||
std::all_of(E->user_begin(), E->user_end(), [this](User *U) {
return ScalarToTreeEntry.count(U) > 0;
}))
if (areAllUsersVectorized(E))
// Take credit for instruction that will become dead.
DeadCost +=
TTI->getVectorInstrCost(Instruction::ExtractElement, VecTy, i);